(2x+3)^2=9x^2-6x+1

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Solution for (2x+3)^2=9x^2-6x+1 equation: 



(2x+3)^2=9x^2-6x+1

We move all terms to the left:

(2x+3)^2-(9x^2-6x+1)=0

We get rid of parentheses

-9x^2+(2x+3)^2+6x-1=0

We add all the numbers together, and all the variables

-9x^2+6x+(2x+3)^2-1=0

We move all terms containing x to the left, all other terms to the right

-9x^2+6x+(2x+3)^2=1

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